x^2+37x+176=0

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Solution for x^2+37x+176=0 equation:



x^2+37x+176=0
a = 1; b = 37; c = +176;
Δ = b2-4ac
Δ = 372-4·1·176
Δ = 665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{665}}{2*1}=\frac{-37-\sqrt{665}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{665}}{2*1}=\frac{-37+\sqrt{665}}{2} $

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